Pressure at the base in Full Stokes
Posted: 07 Mar 2016, 06:26
Hi,
I've been looking at the pressure values at the bottom row of nodes when solving full Stokes, and noticed that the values are different (and usually lower) than purely hydrostatic pressure. I figured out that it is because the pressure being output is for the normal-tangential coordinate system, even though I have "Back Rotate N-T Solution = Logical True". Is there a setting to make sure that the pressure is also converted back to the standard Cartesian coordinate system?
Cheers,
Evan
I've been looking at the pressure values at the bottom row of nodes when solving full Stokes, and noticed that the values are different (and usually lower) than purely hydrostatic pressure. I figured out that it is because the pressure being output is for the normal-tangential coordinate system, even though I have "Back Rotate N-T Solution = Logical True". Is there a setting to make sure that the pressure is also converted back to the standard Cartesian coordinate system?
Cheers,
Evan