Hi everyone,
I have a small problem computing viewfactors in an axi symmetric modell. When I use 2D cartesian coordinates everything works as expected. When I change the coordinate system to axi symmetric, all the view factors a zero.
Is there a reason for this behavior?
Best,
carsten
Viewfactor computation in axi symmetric modell
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Re: Viewfactor computation in axi symmetric modell
Hi
When you choose axisymmetric coordinates then (x,y) is assumed to be (r,z). The symmetry axis is at x=0 and you should not have negative values in the system. Other than that they should work quite the same way.
-Peter
When you choose axisymmetric coordinates then (x,y) is assumed to be (r,z). The symmetry axis is at x=0 and you should not have negative values in the system. Other than that they should work quite the same way.
-Peter
Re: Viewfactor computation in axi symmetric modell
Hi Peter,
thanks for the quick reply.
I found the problem. There was a boundary edge at x = 0 which was set as diffuse radiation boundary. Removing the edge solved the problem.
Just for clarification, the symmetry axis is always assumed to be at x = 0? So If I have a rectangle with x = [xMin,xMax] x > 0, the axi symmetric model be a cylinder shell with rMin = xMin and rMax = xMax?
Is there a way to manually specify the rotation axis?
carsten
thanks for the quick reply.
I found the problem. There was a boundary edge at x = 0 which was set as diffuse radiation boundary. Removing the edge solved the problem.
Just for clarification, the symmetry axis is always assumed to be at x = 0? So If I have a rectangle with x = [xMin,xMax] x > 0, the axi symmetric model be a cylinder shell with rMin = xMin and rMax = xMax?
Is there a way to manually specify the rotation axis?
carsten